Question
Answer Key
Worked Solution
RI/2021/JC1/Promo/P1/Q01
A curve $C$ has equation $y=\frac{a x+b}{c x-2}$, where $a, b$ and $c$ are constants. It is given that $C$ passes through the points with coordinates $(1,5)$ and $(-8,0.5)$. The curve $C$ is translated 1 unit in the positive $x$-direction. The new curve passes through the point with coordinates $(0,-0.2)$. Find the values of $a, b$ and $c$.
From GG $a=2, b=3$ and $c=3$, i.e. $y=\frac{2 x+3}{3 x-2}$
$y=\frac{a x+b}{c x-2}$
Sub $(1,5)$ and $(-8,0.5)$ into equation,
$a+b-5 c=-10-(1)$
$8 a-b-4 c=1 \ldots(2)$
After transformation, the translated curve is $y=\frac{a(x-1)+b}{c(x-1)-2}$.
Substitute $(0,-0.2)$, we get $5 a-5 b+c=-2$
From GG $a=2, b=3$ and $c=3$, i.e. $y=\frac{2 x+3}{3 x-2}$