(i)

(ii) $x<3-\sqrt{\frac{6}{a}}$ or $\sqrt{9-\frac{6}{a}}<x<3$ or $3<x<3+\sqrt{\frac{6}{a}}$

(i)

(ii)The reflected part of $y=\left|\frac{a x-3 a+2}{3-x}\right|_{\text {is }}-\frac{a x-3 a+2}{3-x}$.
Solving $-\frac{a x-3 a+2}{3-x}=\frac{a}{3} x$ :
$a x-3 a+2=\frac{a}{3} x^2-a x$
$a x^2-6 a x+9 a-6=0$

$\begin{aligned} x &=\frac{6 a \pm \sqrt{(-6 a)^2-4(a)(9 a-6)}}{2 a} \\ &=\frac{6 a \pm \sqrt{24 a}}{2 a}=3 \pm \sqrt{\frac{6}{a}} \end{aligned}$

Solving $\frac{a x-3 a+2}{3-x}=\frac{a}{3} x$ :
$$\begin{array}{l}
\frac{a}{3} x^2-3 a+2=0 \\
x^2=\frac{9 a-6}{a} \\
x=\sqrt{9-\frac{6}{a}}\left(\text { Reject } x=-\sqrt{9-\frac{6}{a}}\right)
\end{array}$$

$\therefore\left|\frac{a x-3 a+5}{3-x}\right|>\frac{a}{3} x$
$\Rightarrow x<3-\sqrt{\frac{6}{a}}$ or $\sqrt{9-\frac{6}{a}}<x<3$ or $3<x<3+\sqrt{\frac{6}{a}}$