Question
Answer Key
Worked Solution
9758/2021/P1/Q01
A function $\mathrm{f}$ is defined by $\mathrm{f}(x)=a x^3+b x^2+c x+d$. The graph of $y=\mathrm{f}(x)$ passes through the points $(1,5)$ and $(-1,-3)$. The graph has a turning point at $x=1$, and $\int_0^1 \mathrm{f}(x) \mathrm{d} x=6$.
Find the values of $a, b, c$ and $d$.
$a=4, b=-6, c=0, d=7$
$\mathrm{f}(x)=a x^3+b x^2+c x+d$
When $x=1$,
$y=5 \Rightarrow a+b+c+d=5$
When $x=-1$,
$y=-3 \Rightarrow-a+b-c+d=-3$
$\mathrm{f}^{\prime}(x)=3 a x^2+2 b x+c$
Since $\mathrm{f}^{\prime}(1)=0 \Rightarrow 3 a+2 b+c=0$
$\int_0^1 \mathrm{f}(x) \mathrm{d} x=6$